Peeter Joot's (OLD) Blog.

Math, physics, perl, and programming obscurity.

Pondering a question on conditional probability.

Posted by peeterjoot on December 27, 2011

[Click here for a PDF of this post with nicer formatting and figures if the post had any (especially if my latex to wordpress script has left FORMULA DOES NOT PARSE errors.)]

A bit of confusion.

In [1] section 1.5 while discussing statistical uncertainty is a mention of conditional probability. Once told that a die only rolls numbers up to four, we have a conditional probability for the die of

\begin{aligned}P(i | i \le 4) = \frac{P[i U(i \le 4)]}{P(i \le 4)}= \frac{\frac{1}{{6}}}{\frac{4}{6}} = \frac{1}{{4}}.\end{aligned} \hspace{\stretch{1}}(1.1)

I was having trouble understanding the numerator in this expression. An initial confusion was, “what is this U”. I came to the conclusion that this is just a typo, and was meant to be set intersection, as in

\begin{aligned}P(i | i \le 4) = \frac{P[i \cap (i \le 4)]}{P(i \le 4)}= \frac{\frac{1}{{6}}}{\frac{4}{6}} = \frac{1}{{4}}.\end{aligned} \hspace{\stretch{1}}(1.2)

The denominator makes sense. I picture a sample space with 6 points as in figure (\ref{fig:conditionalProbStatMechalProbStatMechFig1})

Sample space for a die.

The points 1,2,3,4 represent the i \le 4 subspace, as in figure (\ref{fig:conditionalProbStatMechalProbStatMechFig2})

 

 

 

So we have a 4/6 probability for that compound event.

I found it easy to get mixed up considering the numerator. I was envisioning, as in figure (\ref{fig:conditionalProbStatMech:conditionalProbStatMechFig3})

a set of six intersecting with the set of points 1,2,3,4, which is just that set of four. To clear up the confusion, imagine instead that we are asking about the probability of finding the i = 2 face in the dice roll, given the fact that the die only rolls i = 1, 2, 3, 4. Our intersection sample space for that event is then shown in figure

The intersection is just the single point, so we have a 1/6 probability for that compound event. The final result makes sense, since if we are looking for the probability for any of the i = 1, 2, 3, 4 events given that the die will only roll one of these values, we should have a value of 1/4 as found through the compound probability formula.

References

[1] E.A. Jackson. Equilibrium statistical mechanics. Dover Pubns, 2000.

Advertisements

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

 
%d bloggers like this: