## PHY450H1S. Relativistic Electrodynamics Tutorial 5 (TA: Simon Freedman). Angular momentum of EM fields

Posted by peeterjoot on March 10, 2011

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# Motivation.

Long solenoid of radius , n turns per unit length, current . Coaxial with with solenoid are two long cylindrical shells of length and of , and respectively, where .

When current is gradually reduced what happens?

## The initial fields.

### Initial Magnetic field.

For the initial static conditions where we have only a (constant) magnetic field, the Maxwell-Ampere equation takes the form

\paragraph{On the name of this equation}. In notes from one of the lectures I had this called Maxwell-Faraday equation, despite the fact that this isn’t the one that Maxwell made his displacement current addition. Did the Professor call it that, or was this my addition? In [2] Faraday’s law is also called the Maxwell-Faraday equation. [1] calls this the Ampere-Maxwell equation, which makes more sense.

Put into integral form by integrating over an open surface we have

The current density passing through the surface is defined as the enclosed current, circulating around the bounding loop

so by Stokes Theorem we write

Now consider separately the regions inside and outside the cylinder. Inside we have

Outside of the cylinder we have the equivalent of loops, each with current , so we have

Our magnetic field is constant while is constant, and in vector form this is

### Initial Electric field.

How about the electric fields?

For $latex r b$ we have since there is no charge enclosed by any Gaussian surface that we choose.

Between and we have, for a Gaussian surface of height (assuming that )

so we have

### Poynting vector before the current changes.

Our Poynting vector, the energy flux per unit time, is

This is non-zero only in the region both between the solenoid and the enclosing cylinder (radius ) since that’s the only place where both and are non-zero. That is

(since , so after cyclic permutation)

### A motivational aside: Momentum density.

Suppose , then our Poynting vector is

but

so

Now recall the between (relativistic) mechanical momentum and energy

This justifies calling the quantity

the momentum density.

### Momentum density of the EM fields.

So we label our scaled Poynting vector the momentum density for the field

and can now compute an angular momentum density in the field between the solenoid and the outer cylinder prior to changing the currents

This gives us

Note that this is the angular momentum density in the region between the solenoid and the inner cylinder, between and . Outside of this region, the angular momentum density is zero.

## After the current is changed

### Induced electric field

When we turn off (or change) , some of the magnetic field will be converted into electric field according to Faraday’s law

In integral form, utilizing an open surface, this is

where we introduce the magnetic flux

We can utilizing a circular surface cutting directly across the cylinder perpendicular to of radius . Recall that we have the magnetic field 1.7 only inside the solenoid. So for this flux is

For only the portion of the surface with radius contributes to the flux

We can now compute the circulation of the electric field

by taking the derivatives of the magnetic flux. For this is

This gives us the magnitude of the induced electric field

Similarly for we have

Summarizing we have

latex r R$}\end{array}\right.\end{aligned} \hspace{\stretch{1}}(1.22)$

### Torque and angular momentum induced by the fields.

Our torque on the outer cylinder (radius ) that is induced by changing the current is

This provides the induced angular momentum on the outer cylinder

This is the angular momentum of induced by changing the current or changing the magnetic field.

On the inner cylinder we have

So our induced angular momentum on the inner cylinder is

The total angular momentum in the system has to be conserved, and we must have

At the end of the tutorial, this sum was equated with the field angular momentum density , but this has different dimensions. In fact, observe that the volume in which this angular momentum density is non-zero is the difference between the volume of the solenoid and the inner cylinder

so if we are to integrate the angular momentum density 1.17 over this region we have

which does match with the sum of the mechanical angular momentum densities 1.24 as expected.

# References

[1] D. Fleisch. *A Student’s Guide to Maxwell’s Equations*. Cambridge University Press, 2007. “http://www4.wittenberg.edu/maxwell/index.html“.

[2] Wikipedia. Faraday’s law of induction — wikipedia, the free encyclopedia [online]. 2011. [Online; accessed 10-March-2011]. http://en.wikipedia.org/w/index.php?title=Faraday\%27s_law_of_induction&oldid=416715237.

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