## PHY356F: Quantum Mechanics I. Lecture 11 notes. Harmonic Oscillator.

Posted by peeterjoot on November 30, 2010

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# Setup.

Why study this problem?

It is relevant to describing the oscillation of molecules, quantum states of light, vibrations of the lattice structure of a solid, and so on.

FIXME: projected picture of masses on springs, with a ladle shaped well, approximately Harmonic about the minimum of the bucket.

The problem to solve is the one dimensional Hamiltonian

where is the mass, is the frequency, is the position operator, and is the momentum operator. Of these quantities, and are classical quantities.

This problem can be used to illustrate some of the reasons why we study the different pictures (Heisenberg, Interaction and Schr\”{o}dinger). This is a problem well suited to all of these (FIXME: lookup an example of this with the interaction picture. The book covers H and S methods.

We attack this with a non-intuitive, but cool technique. Introduce the raising and lowering operators:

\paragraph{Question:} are we using the dagger for more than Hermitian conjugation in this case.

\paragraph{Answer:} No, this is precisely the Hermitian conjugation operation.

Solving for and in terms of and , we have

or

Express in terms of and

Since then we can show that . Solve for as follows

Comparing LHS and RHS we have as stated

and thus from 8.175 we have

Let be the eigenstate of so that . From 8.177 we have

or

We wish now to find the eigenstates of the “Number” operator , which are simultaneously eigenstates of the Hamiltonian operator.

Observe that we have

where we used .

or

The new state is presumed to lie in the same space, expressible as a linear combination of the basis states in this space. We can see the effect of the operator on this new state, we find that the energy is changed, but the state is otherwise unchanged. Any state is an eigenstate of , and therefore also an eigenstate of the Hamiltonian.

Play the same game and win big by discovering that

There will be some state such that

which implies

so from 8.180 we have

Observe that we can identify for

or

or

where .

We can write

or

We call this operator , the number operator, so that

# Relating states.

Recall the calculation we performed for

Where , and are constants. The next game we are going to play is to work out for the lowering operation

and the raising operation

For the Hermitian conjugate of we have

So

Expanding the LHS we have

For

Similarly

and

for

# Heisenberg picture.

\paragraph{How does the lowering operator evolve in time?}

\paragraph{A:} Recall that for a general operator , we have for the time evolution of that operator

Let’s solve this one.

Even though is an operator, it can undergo a time evolution and we can think of it as a function, and we can solve for in the differential equation

This has the solution

here is an operator, the value of that operator at . The exponential here is just a scalar (not effected by the operator so we can put it on either side of the operator as desired).

\paragraph{CHECK:}

# A couple comments on the Schr\”{o}dinger picture.

We don’t do this in class, but it is very similar to the approach of the hydrogen atom. See the text for full details.

In the Schr\”{o}dinger picture,

This does directly to the wave function representation, but we can relate these by noting that we get this as a consequence of the identification .

In 11.204, we can switch to dimensionless quantities with

with

This gives, with ,

We can use polynomial series expansion methods to solve this, and find that we require a terminating expression, and write this in terms of the Hermite polynomials (courtesy of the clever French once again).

When all is said and done we will get the energy eigenvalues once again

# Back to the Heisenberg picture.

Let us express

With

we have

and

Recall that our matrix operator is

We have then

NOTE: picture of the solution to this LDE on slide…. but I didn’t look closely enough.

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